Optimal. Leaf size=367 \[ -\frac{7 (-4 B+i A)}{24 d \sqrt{\cot (c+d x)} \left (a^3 \cot (c+d x)+i a^3\right )}+\frac{5 (A+6 i B)}{8 a^3 d \sqrt{\cot (c+d x)}}+\frac{\left (\frac{1}{32}+\frac{i}{32}\right ) ((6+i) A+(1+29 i) B) \log \left (\cot (c+d x)-\sqrt{2} \sqrt{\cot (c+d x)}+1\right )}{\sqrt{2} a^3 d}-\frac{\left (\frac{1}{32}+\frac{i}{32}\right ) ((6+i) A+(1+29 i) B) \log \left (\cot (c+d x)+\sqrt{2} \sqrt{\cot (c+d x)}+1\right )}{\sqrt{2} a^3 d}+\frac{\left (\frac{1}{16}+\frac{i}{16}\right ) ((1+6 i) A-(29+i) B) \tan ^{-1}\left (1-\sqrt{2} \sqrt{\cot (c+d x)}\right )}{\sqrt{2} a^3 d}+\frac{((5-7 i) A+(28+30 i) B) \tan ^{-1}\left (\sqrt{2} \sqrt{\cot (c+d x)}+1\right )}{16 \sqrt{2} a^3 d}+\frac{2 A+5 i B}{12 a d \sqrt{\cot (c+d x)} (a \cot (c+d x)+i a)^2}+\frac{-B+i A}{6 d \sqrt{\cot (c+d x)} (a \cot (c+d x)+i a)^3} \]
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Rubi [A] time = 0.925566, antiderivative size = 367, normalized size of antiderivative = 1., number of steps used = 15, number of rules used = 10, integrand size = 36, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.278, Rules used = {3581, 3596, 3529, 3534, 1168, 1162, 617, 204, 1165, 628} \[ -\frac{7 (-4 B+i A)}{24 d \sqrt{\cot (c+d x)} \left (a^3 \cot (c+d x)+i a^3\right )}+\frac{5 (A+6 i B)}{8 a^3 d \sqrt{\cot (c+d x)}}+\frac{\left (\frac{1}{32}+\frac{i}{32}\right ) ((6+i) A+(1+29 i) B) \log \left (\cot (c+d x)-\sqrt{2} \sqrt{\cot (c+d x)}+1\right )}{\sqrt{2} a^3 d}-\frac{\left (\frac{1}{32}+\frac{i}{32}\right ) ((6+i) A+(1+29 i) B) \log \left (\cot (c+d x)+\sqrt{2} \sqrt{\cot (c+d x)}+1\right )}{\sqrt{2} a^3 d}+\frac{\left (\frac{1}{16}+\frac{i}{16}\right ) ((1+6 i) A-(29+i) B) \tan ^{-1}\left (1-\sqrt{2} \sqrt{\cot (c+d x)}\right )}{\sqrt{2} a^3 d}+\frac{((5-7 i) A+(28+30 i) B) \tan ^{-1}\left (\sqrt{2} \sqrt{\cot (c+d x)}+1\right )}{16 \sqrt{2} a^3 d}+\frac{2 A+5 i B}{12 a d \sqrt{\cot (c+d x)} (a \cot (c+d x)+i a)^2}+\frac{-B+i A}{6 d \sqrt{\cot (c+d x)} (a \cot (c+d x)+i a)^3} \]
Antiderivative was successfully verified.
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Rule 3581
Rule 3596
Rule 3529
Rule 3534
Rule 1168
Rule 1162
Rule 617
Rule 204
Rule 1165
Rule 628
Rubi steps
\begin{align*} \int \frac{A+B \tan (c+d x)}{\cot ^{\frac{7}{2}}(c+d x) (a+i a \tan (c+d x))^3} \, dx &=\int \frac{B+A \cot (c+d x)}{\cot ^{\frac{3}{2}}(c+d x) (i a+a \cot (c+d x))^3} \, dx\\ &=\frac{i A-B}{6 d \sqrt{\cot (c+d x)} (i a+a \cot (c+d x))^3}+\frac{\int \frac{-\frac{1}{2} a (A+13 i B)-\frac{7}{2} a (i A-B) \cot (c+d x)}{\cot ^{\frac{3}{2}}(c+d x) (i a+a \cot (c+d x))^2} \, dx}{6 a^2}\\ &=\frac{i A-B}{6 d \sqrt{\cot (c+d x)} (i a+a \cot (c+d x))^3}+\frac{2 A+5 i B}{12 a d \sqrt{\cot (c+d x)} (i a+a \cot (c+d x))^2}+\frac{\int \frac{a^2 (4 i A-31 B)-5 a^2 (2 A+5 i B) \cot (c+d x)}{\cot ^{\frac{3}{2}}(c+d x) (i a+a \cot (c+d x))} \, dx}{24 a^4}\\ &=\frac{i A-B}{6 d \sqrt{\cot (c+d x)} (i a+a \cot (c+d x))^3}+\frac{2 A+5 i B}{12 a d \sqrt{\cot (c+d x)} (i a+a \cot (c+d x))^2}-\frac{7 (i A-4 B)}{24 d \sqrt{\cot (c+d x)} \left (i a^3+a^3 \cot (c+d x)\right )}+\frac{\int \frac{15 a^3 (A+6 i B)+21 a^3 (i A-4 B) \cot (c+d x)}{\cot ^{\frac{3}{2}}(c+d x)} \, dx}{48 a^6}\\ &=\frac{5 (A+6 i B)}{8 a^3 d \sqrt{\cot (c+d x)}}+\frac{i A-B}{6 d \sqrt{\cot (c+d x)} (i a+a \cot (c+d x))^3}+\frac{2 A+5 i B}{12 a d \sqrt{\cot (c+d x)} (i a+a \cot (c+d x))^2}-\frac{7 (i A-4 B)}{24 d \sqrt{\cot (c+d x)} \left (i a^3+a^3 \cot (c+d x)\right )}+\frac{\int \frac{21 a^3 (i A-4 B)-15 a^3 (A+6 i B) \cot (c+d x)}{\sqrt{\cot (c+d x)}} \, dx}{48 a^6}\\ &=\frac{5 (A+6 i B)}{8 a^3 d \sqrt{\cot (c+d x)}}+\frac{i A-B}{6 d \sqrt{\cot (c+d x)} (i a+a \cot (c+d x))^3}+\frac{2 A+5 i B}{12 a d \sqrt{\cot (c+d x)} (i a+a \cot (c+d x))^2}-\frac{7 (i A-4 B)}{24 d \sqrt{\cot (c+d x)} \left (i a^3+a^3 \cot (c+d x)\right )}+\frac{\operatorname{Subst}\left (\int \frac{-21 a^3 (i A-4 B)+15 a^3 (A+6 i B) x^2}{1+x^4} \, dx,x,\sqrt{\cot (c+d x)}\right )}{24 a^6 d}\\ &=\frac{5 (A+6 i B)}{8 a^3 d \sqrt{\cot (c+d x)}}+\frac{i A-B}{6 d \sqrt{\cot (c+d x)} (i a+a \cot (c+d x))^3}+\frac{2 A+5 i B}{12 a d \sqrt{\cot (c+d x)} (i a+a \cot (c+d x))^2}-\frac{7 (i A-4 B)}{24 d \sqrt{\cot (c+d x)} \left (i a^3+a^3 \cot (c+d x)\right )}-\frac{((5+7 i) A-(28-30 i) B) \operatorname{Subst}\left (\int \frac{1-x^2}{1+x^4} \, dx,x,\sqrt{\cot (c+d x)}\right )}{16 a^3 d}+\frac{((5-7 i) A+(28+30 i) B) \operatorname{Subst}\left (\int \frac{1+x^2}{1+x^4} \, dx,x,\sqrt{\cot (c+d x)}\right )}{16 a^3 d}\\ &=\frac{5 (A+6 i B)}{8 a^3 d \sqrt{\cot (c+d x)}}+\frac{i A-B}{6 d \sqrt{\cot (c+d x)} (i a+a \cot (c+d x))^3}+\frac{2 A+5 i B}{12 a d \sqrt{\cot (c+d x)} (i a+a \cot (c+d x))^2}-\frac{7 (i A-4 B)}{24 d \sqrt{\cot (c+d x)} \left (i a^3+a^3 \cot (c+d x)\right )}+\frac{((5+7 i) A-(28-30 i) B) \operatorname{Subst}\left (\int \frac{\sqrt{2}+2 x}{-1-\sqrt{2} x-x^2} \, dx,x,\sqrt{\cot (c+d x)}\right )}{32 \sqrt{2} a^3 d}+\frac{((5+7 i) A-(28-30 i) B) \operatorname{Subst}\left (\int \frac{\sqrt{2}-2 x}{-1+\sqrt{2} x-x^2} \, dx,x,\sqrt{\cot (c+d x)}\right )}{32 \sqrt{2} a^3 d}+\frac{((5-7 i) A+(28+30 i) B) \operatorname{Subst}\left (\int \frac{1}{1-\sqrt{2} x+x^2} \, dx,x,\sqrt{\cot (c+d x)}\right )}{32 a^3 d}+\frac{((5-7 i) A+(28+30 i) B) \operatorname{Subst}\left (\int \frac{1}{1+\sqrt{2} x+x^2} \, dx,x,\sqrt{\cot (c+d x)}\right )}{32 a^3 d}\\ &=\frac{5 (A+6 i B)}{8 a^3 d \sqrt{\cot (c+d x)}}+\frac{i A-B}{6 d \sqrt{\cot (c+d x)} (i a+a \cot (c+d x))^3}+\frac{2 A+5 i B}{12 a d \sqrt{\cot (c+d x)} (i a+a \cot (c+d x))^2}-\frac{7 (i A-4 B)}{24 d \sqrt{\cot (c+d x)} \left (i a^3+a^3 \cot (c+d x)\right )}+\frac{((5+7 i) A-(28-30 i) B) \log \left (1-\sqrt{2} \sqrt{\cot (c+d x)}+\cot (c+d x)\right )}{32 \sqrt{2} a^3 d}-\frac{((5+7 i) A-(28-30 i) B) \log \left (1+\sqrt{2} \sqrt{\cot (c+d x)}+\cot (c+d x)\right )}{32 \sqrt{2} a^3 d}+\frac{((5-7 i) A+(28+30 i) B) \operatorname{Subst}\left (\int \frac{1}{-1-x^2} \, dx,x,1-\sqrt{2} \sqrt{\cot (c+d x)}\right )}{16 \sqrt{2} a^3 d}-\frac{((5-7 i) A+(28+30 i) B) \operatorname{Subst}\left (\int \frac{1}{-1-x^2} \, dx,x,1+\sqrt{2} \sqrt{\cot (c+d x)}\right )}{16 \sqrt{2} a^3 d}\\ &=-\frac{((5-7 i) A+(28+30 i) B) \tan ^{-1}\left (1-\sqrt{2} \sqrt{\cot (c+d x)}\right )}{16 \sqrt{2} a^3 d}+\frac{((5-7 i) A+(28+30 i) B) \tan ^{-1}\left (1+\sqrt{2} \sqrt{\cot (c+d x)}\right )}{16 \sqrt{2} a^3 d}+\frac{5 (A+6 i B)}{8 a^3 d \sqrt{\cot (c+d x)}}+\frac{i A-B}{6 d \sqrt{\cot (c+d x)} (i a+a \cot (c+d x))^3}+\frac{2 A+5 i B}{12 a d \sqrt{\cot (c+d x)} (i a+a \cot (c+d x))^2}-\frac{7 (i A-4 B)}{24 d \sqrt{\cot (c+d x)} \left (i a^3+a^3 \cot (c+d x)\right )}+\frac{((5+7 i) A-(28-30 i) B) \log \left (1-\sqrt{2} \sqrt{\cot (c+d x)}+\cot (c+d x)\right )}{32 \sqrt{2} a^3 d}-\frac{((5+7 i) A-(28-30 i) B) \log \left (1+\sqrt{2} \sqrt{\cot (c+d x)}+\cot (c+d x)\right )}{32 \sqrt{2} a^3 d}\\ \end{align*}
Mathematica [A] time = 4.33462, size = 280, normalized size = 0.76 \[ \frac{\sec ^2(c+d x) (\cos (d x)+i \sin (d x))^3 (A+B \tan (c+d x)) \left (\frac{2}{3} (\cos (3 d x)-i \sin (3 d x)) ((9 A+33 i B) \cos (c+d x)+21 (A+7 i B) \cos (3 (c+d x))+2 i \sin (c+d x) ((19 A+145 i B) \cos (2 (c+d x))+19 A+97 i B))-i (\cos (3 c)+i \sin (3 c)) \sqrt{\sin (2 (c+d x))} \csc (c+d x) \left (((7+5 i) A-(30-28 i) B) \sin ^{-1}(\cos (c+d x)-\sin (c+d x))+(1-i) ((6+i) A+(1+29 i) B) \log \left (\sin (c+d x)+\sqrt{\sin (2 (c+d x))}+\cos (c+d x)\right )\right )\right )}{32 d \sqrt{\cot (c+d x)} (a+i a \tan (c+d x))^3 (A \cos (c+d x)+B \sin (c+d x))} \]
Antiderivative was successfully verified.
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Maple [C] time = 0.635, size = 6350, normalized size = 17.3 \begin{align*} \text{output too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: RuntimeError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 1.767, size = 2064, normalized size = 5.62 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: AttributeError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{B \tan \left (d x + c\right ) + A}{{\left (i \, a \tan \left (d x + c\right ) + a\right )}^{3} \cot \left (d x + c\right )^{\frac{7}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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